18c^2-27c=0

Solution for 18c^2-27c=0 equation:

18c^2-27c=0

a = 18; b = -27; c = 0;
Δ = b2-4ac
Δ = -272-4·18·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-27}{2*18}=\frac{0}{36}
=0
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+27}{2*18}=\frac{54}{36}
=1+1/2
$